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Two identical resistors use 60 W in series. Reconnect them in parallel across the same ideal battery.
The ideal battery keeps voltage constant. Equivalent resistance falls from 2R to R/2. Using P = V²/Req, total power becomes 4 × 60 = 240 W. That is 120 W in each resistor.Practise more like this, freeWatch it solved in under a minute: English · हिंदीOriginal practice · Ideal wires; constant resistor values.
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Marks and negative marking on every question, a question palette to jump between questions, and Back / Next like the real exam.
Review each question with its worked explanation. This one is the 60 W question above.
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Current electricity
Try the next step.
Three identical resistors use 30 W in series. What changes when all three are connected in parallel across the same ideal battery?
Put the formulas to work with our free current-electricity practice pack. Check the conditions, show your reasoning, and return to the questions that challenged you.
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START HERE · ENGLISHOur approach to learning, revision and practice. Watch on YouTube in a new tab.
WORKED PROBLEM · ENGLISHWork out the arrangement for maximum current. Watch on YouTube in a new tab.
WORKED PROBLEM · HINDIFollow the cell-grouping problem in Hindi. Watch on YouTube in a new tab.
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Many JEE Physics Decoded video lessons come in both English and Hindi. The practice app and the downloadable worksheet are in English.
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